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Answer the questions...no need detail explanation Question 1 A university administrator expects that 41% of students in a core course will receive an A. He

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Answer the questions...no need detail explanation

Question 1

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A university administrator expects that 41% of students in a core course will receive an A. He looks at the grades assigned to 80 students, What is the probability that the proportion of students who receive an A is not between 0.33 and 0.44? A. 0.1351 B. 0.3647 C. 0.6353 D. 0.8649Administrative assistants in a local university have been asked to prove their proficiency in the use of spreadsheet software by taking a proficiency test. Historically, the mean test score has been 77 with a standard deviation of 4. A random sample of size 54 is taken from the 120 administrative assistants and asked to complete the proficiency test. 39. Hitung nilai dijangka dan ralat plawal bagi min sampel. A. E(X) - 54 dan se(X) = 0.5443 B. E(X ) = 54 dan se(X) - 0.7447 C. E(X) = 120 dan se(X) -- 0.6293 D. B(X) - 77 dan se(X) = 0.4054 Calculate the expected value and the standard error of the sample mean. A. BOX) - 54 and se(X) = 0.5143 6. EUX = 54 and se(X) - 0.7-H7 C 1(X) - 120 and se(*) = 0.6293 D. B() - 7/ and set )) = 0.4054What is the probability that the sample mean score is at most 767 A. 0.0068 B. 0.0329 C. 0.9671 D. 0.9943

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