answer with working pls

1. Suppose that f(5) = 1, f'(5) = 6, g(5) = -3, and g'(5) = 2. Find the following values. (a) (fg)'(5) ( b) (f/g)' (5 ) (c) (g/f)'(5) - 9 (1) x2 - 1 f(x) = 2x - 3 f (x) = x3/2Let f(x) = x3. 2. (a) Estimate the values of f'(0), f'(;), f'(1), f' (2), and f'(3) 1Differentiate the function. f (x ) = 240 f (t) = 2 -2 f(x) = x3 - 4x+ 6 3. g( t) = t - Vt $ 1/34. Find the derivatives (Chain Rule) h (t) = (t + 1) 2/3 ( 2+2 - 1) 3 F(t) = (3t - 1)4(2t + 1) -3 x2 + 1 3 J = x2 - 1