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Isin 20' Q2 AN 7 207 75 sin 30 75 ca 30 Mq = 75 Balancing forces along inclined planes + dirt N + Isin 20' = 75 cas 30 -( 1) Teas 20" = 75 sin 30" 2 > T = 75 sin30 Cay 20 => T = 39. 9 N 2 ) Ne = 75cas30' - 39, 9 sin 20' > N = 51. 305 NQ 1 160 30 1 O Te 30 N Forces acting on block |TC = 30 N Forces on pt. 0 TA ( 30 ' Q "TrainYo' X TC 7 TA Sin 30 ' = TA ca 30' = Is sin 40' TA = 0.74 TB To cas 40' - Tet TAsin 30 TB cas 40' = 30 + 0. 74 TB sin 30 ' > > 16 = 75-75 N TA = 0 . 74 X 75.75 2 ) TA = 56. 06 N30 KUNDUq KU DU Z mass m = 10kq mass m , = 5kg mig - Te mig T - mgsin 30 = m. 9 -(11 ) my adding (1) * (11) KUN mig - mag sin 30 = (M, + m )q DU z ( m, - m2 sin 30) g 9. ( m , + m 2 ) ( 10 - 5X1 X918 1: 92 98 m /s ? = 9 ( 10+5 ) 9 = 419 M /s 2 Part (2 ) U acceleration of two blocks = 4.9 m /s ?Putting 9= 4,9 m/s2 in ( 1) . 10 x 91 8 - T 2 10 *48 T = 10 * (9,8 - 419 ) = 49 N Part ( 1) ) Tension = 49 N KUNDUZ Part (3 ) = - displacement = - 215 m using H = 4t - lot2 -2+5 2 -1 x 198 - 215 2- 1x 49xt2 KUNDUZ 1 = lil' sec . KUNDUZ Part (4) W = at V = 4.9 x 1,01 - velocity of heavy block = 4. 9497 - 5 m/s KUNDUZ KUNDUZ