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Approximately 0.52 kg is placed a distance of 2 cm to the left of the pivot point of the low mass [negligible] beam as shown

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Approximately 0.52 kg is placed a distance of 2 cm to the left of the pivot point of the low mass [negligible] beam as shown in the image below. How far to the right of fulcrum must a 50 gram mass be placed to bring the system to rotational equilibrium? Please give your answer in units of centimeters, however, do not explicitly include units when typing your answer into the answer box. Including actual units will result in your answer being incorrectly scored

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