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Approximately 10% of all people are left-handed. Consider a grouping of fifteen people. b) The number of trial is fixed n=15 and the probability of

Approximately 10% of all people are left-handed. Consider a grouping of fifteen people.

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b) The number of trial is fixed n=15 and the probability of success is p =0.10 The probability distribution function is, P(X = x) = x ( p) (1-p )"- 15 = (0.10) (1-0.10)-x

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