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as 25 a= (73cm) EXPERIMENT #4 (0.738)2 Newton's Second Law of Motion on the Atwood Machine a= 273.97 cm/s2 Summary of the experiment b. Theoretical

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as 25 a= (73cm) EXPERIMENT #4 (0.738)2 Newton's Second Law of Motion on the Atwood Machine a= 273.97 cm/s2 Summary of the experiment b. Theoretical DATA TABLE Trial 1 Trial 2 Trial 1 2 3 Given: m1= 27.6 g Given: m1= 32.6 g Average time, t (5) 1.71 1.09 0.73 mz= 22.6 g m2= 22.6 9 Heavier mass, m1(9) 27.6 32.6 37.6 a= (12)g Lighter mass, m2 (9) 22.6 22.6 m, +mz)- a= (1-z )g 22.6 (m, +mz) Distance, s (cm) 73 73 73 a= (27.6-22.5) 27.6+22.69 a= 32.6-22.6 (32.6+22.6/9 Value of "a" from equation 1 (cm/s2 49.93 122.89 273.97 5 10 a= Value of "a" from equation 2 (cm/s2 970 18 59000 50.29 35.2 Percent difference (96) a= 0.996 g a= 0.181g Data Analysis (DISSE ) (THE ) = (0.00099 kg) (9.8m/s') (POTE ) (TOOEE) = (0.00018 kg) (9.8m/s!) = 0.0097 N (100000) = 970 cm/s2 = 0.0018 N (100000) = 18 cm/52 Calculations a= 970 cm/s2 a= 18 cm/$2 a. Experimental Trial 1 Trial 2 Trial 3 Given: Average Time= 1.71s Given: Average Time= 1.095 Given: m1= 37.6 9 a= 15 50.29 Distance= 73cm Distance= 73cm mz= 22.6 g a= 60.2 g as 25 a= 25 a= (mamz) (m, +m 19 (IDogg = (0.0602kg) (9.8m/s') = a= (73cm) a- 2 (73cm) (1.718)2 (1.095)2 37.6-22.6) 37.6+22.69 0.59 N (100000) = 59000 cm/52 a= 49.93 cm/s2 a= 122.89 cm/52 a= 59000cm/52 Trial 3 Given: Average Time= 0.735 Distance= 73cm QUESTIONSConclusion: 1. Explain the difference in the results of the two equations of acceleration used in the experiment. 2. In the experiment, if friction were present between the shaft and pulley, will the system have a greater or lesser acceleration than when it has no friction? Why? 3. A stalled 1,000- kg car needs a push. Starting at rest, how hard do you have to push to get it up to 10 m/sec in 100 seconds? 4. A ball of mass m1 and a block of mass m2 are attached by a lightweight cord that passes over a frictionless pulley of negligible mass, as shown in the Figure 1.1. The block lies on a frictionless incline of angle 0. a. Find the magnitude of the acceleration of the two objects and the tension in the cord. b. What happens in this situation if the angle 0 = 900? c. What happens if the mass m1 = 0? Figure 1.1 Illustration taken from Physics for Scientists and Engineers 6th Edition by Serway & Jewett

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