As discussed during the lecture, the enzyme HIV$-1$ reverse transcriptae $($HIV$-$RT$)$ plays a significant role for the HIV virus and is an important drug target. Assume a concentration $[$E$]$ of $2\mathrm{.}00$M $($i$.$e$.2\mathrm{.}00$ x $10-6$ mol$/$l$)$ for HIV$-$RT$.$ Two potential drug molecules, D$1$ and D$2,$ were identified, which form stable complexes with the HIV$-$RT$.$

The dissociation constant of the complex ED$1$ formed by HIV$-$RT and the drug D$1$ is $1\mathrm{.}00$ nM $($i$.$e$.1\mathrm{.}00$ x $10-9).$ The dissociation constant of the complex ED$2$ formed by HIV$-$RT and the drug D$2$ is $100$ nM $($i$.$e$.1\mathrm{.}00$ x $10-7)\mathrm{.}1.$ Divide the difference between the binding free energies of the ED$1$ and ED$2$ complexes by the thermal energy $($at the physiological temperature $310$K$).$ Provide a numerical expression with $3$ significant figures. $2.$ Compute the total concentration of $[$D$2]$tot that is needed to bind $99\%$ of the HIV$-$RT at the given concentration $[$E$]$tot$.$ Provide your answer as a numerical expression with $3$ significant figures in the unit mol$/$l$.$

You do NOT have to consider competition betwwen the drugs D$1$ and D$2!$ They are administered separately.