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As shown in the diagram, a water molecule at the origin is a permanent electric dipole: it is charged positively on the left where

  

As shown in the diagram, a water molecule at the origin is a "permanent electric dipole": it is charged positively on the left where the two hydrogen atoms are, and is charged negatively on the right where the oxygen atom is. This combination of charges exerts a force to the right on an electron located to the right of the water molecule. The force is to the right because the negatively charged region of the water molecule is closer to the electron than is the positively charged region. The force exerted on the electron is not proportional to 1/x because the effects of the positive and negative regions of the water molecule nearly cancel each other out. Rather, the force on the electron is proportional to 1/x and is equal to 1.12 10-19 e/x N, where the magnitude of the electron charge is e = 1.6 10-19 C. The electron is initially at rest at x; = 16 10-10 m. It accelerates to the right, along the x axis. At the moment that it passes x = 25 10-10 m, how much work has been done on the electron? (Because the water molecule's mass is much greater than the electron's mass, the water molecule hardly moves during this time.) work= + H H Water molecule Electron

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