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as user enters 'hit' i want the program to add another random number (generated from the fog() function) but the new numbers keep chnaging as
as user enters 'hit' i want the program to add another random number (generated from the fog() function) but the new numbers keep chnaging as i enter hit.
this is my goal:
the 2 given numbers are: 2,4
and if user enters hit it chnages it to 2,4,6
and if user enter hit again it should say 2,4,6,7
but in my program the new random numbers keep changing, is there a way to get around this ?
my python program:
def play():
x = 0
c = ['2','3','4','5','6','7','8','9','J','Q','K','A']
a = random.choice(c)
print(a)
if a == '2' or a == '3' or a == '4' or a == '5' or a == '6' or a == '7' or a == '8' or a == '9':
x = int(a)
elif a == 'K' or a == 'J' or a == 'Q':
x = 10
x = int(x)
elif a == 'A':
one = random.randint(1,2)
if one == 2:
x = 11
x = int(x)
else:
x = 1
x = int(x)
y = 0
d = ['2','3','4','5','6','7','8','9','J','Q','','A']
b = random.choice(d)
print(b)
if b == '2' or b == '3' or b == '4' or b == '5' or b == '6' or b == '7' or b == '8' or b == '9':
y = int(b)
elif b == 'K' or b == 'J' or b == 'Q':
y = 10
y = int(y)
elif b == 'A':
one = random.randint(1,2)
if one == 2:
y = 11
y = int(y)
else:
y = 1
y = int(y)
print(x+y)
loser = 0
more = 0
while loser
ask = input("Hit or stand? ")
if ask == 'hit':
more += 1
if more == 1:
loser = x+y+fog()
print(f"Your current hand: {x} {y} {fog()} {loser}")
if more == 2:
loser = x+y+fog()+fog()
print(f"Your current hand: {x} {y} {fog()} {fog()} {loser}")
elif ask == 'stand':
break
def fog():
score = 0
x = 0
c = ['2','3','4','5','6','7','8','9','J','Q','K','A']
a = random.choice(c)
if a == '2' or a == '3' or a == '4' or a == '5' or a == '6' or a == '7' or a == '8' or a == '9':
x = int(a)
if a == 'K' or a == 'J' or a == 'Q':
x = 10
x = int(x)
elif a == 'A':
one = random.randint(1,2)
if one == 2:
x = 11
x = int(x)
else:
x = 1
x = int(x)
return x
play()
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