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Suppose that the crystal oscillator frequency is 1Mhz, compute the the execution time of the following code in microseconds REG EQU 10H MOVLW D'20'

 


Suppose that the crystal oscillator frequency is 1Mhz, compute the the execution time of the following code in microseconds REG EQU 10H MOVLW D'20' MOVWF REG AGAIN BRA NN NOP NOP NN NOP DECF REG BNZ AGAIN

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Clock frequency of the system 1MHz Clock perios T 1f 4 10 6 114 10 6 025 uS now REG ... blur-text-image

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