Assign Considering a simple BSS topology where all the STAs can hear each other (i.e., no hidden node, exposed terminal case), draw the frame scheduling for the following transmission sequence using the DCF scheme. RTS/CTS IS used TXOP of duration 25, NO frame aggregation, NO block ACK Retry count = 2 Traffic: STA#1 -> AP: 4 frames (length: 6, 12, 10, and 15 start: 3, 3, 3, and 31) AP -> STA#3: 2 frames (length: 5 and 15, start: 2 and 9) STA#2 -> STA#1: 2 frames (length 4 and 9, start 2 and 14) Timings: SIFS: 1 unit, DIFS: 3 unit, ACK: 1 unit, RTS: 1 unit, CTS: 1 unit, CW_min = 7 (8-1), CW_max = 31 (32-1) Also, for each node, there is a random number generator that gives the following output for each node. When calculating a backoff duration, round down the resulting number. AP 0.3 0.4 0.5 0.4 0.3 1 0.9 0.4 0.3 0.6 0.4 STA1 0.4 0.8 0.3 0.1 0.2 0 1 0.5 0.5 0.6 0.7 STA2 0.2 1 0.7 0.3 0.7 0.7 0 0.3 0.7 0.9 0.4 Assign Considering a simple BSS topology where all the STAs can hear each other (i.e., no hidden node, exposed terminal case), draw the frame scheduling for the following transmission sequence using the DCF scheme. RTS/CTS IS used TXOP of duration 25, NO frame aggregation, NO block ACK Retry count = 2 Traffic: STA#1 -> AP: 4 frames (length: 6, 12, 10, and 15 start: 3, 3, 3, and 31) AP -> STA#3: 2 frames (length: 5 and 15, start: 2 and 9) STA#2 -> STA#1: 2 frames (length 4 and 9, start 2 and 14) Timings: SIFS: 1 unit, DIFS: 3 unit, ACK: 1 unit, RTS: 1 unit, CTS: 1 unit, CW_min = 7 (8-1), CW_max = 31 (32-1) Also, for each node, there is a random number generator that gives the following output for each node. When calculating a backoff duration, round down the resulting number. AP 0.3 0.4 0.5 0.4 0.3 1 0.9 0.4 0.3 0.6 0.4 STA1 0.4 0.8 0.3 0.1 0.2 0 1 0.5 0.5 0.6 0.7 STA2 0.2 1 0.7 0.3 0.7 0.7 0 0.3 0.7 0.9 0.4