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Assume a demand equation: 0d = 9 - 0.1p - pa + 0.01;}S + 0.00011 and a supply equation: Q5 : 0.1p - 0.02m 1-

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Assume a demand equation: 0d = 9 - 0.1p - pa + 0.01;}S + 0.00011\" and a supply equation: Q5 : 0.1p - 0.02m 1- 0.01N + 0.01T - 0.1w where p = price of the good D = quantity.r in thousands of units pa = price ofa complement = $3 Pi = price of an input = $450 pg: price of a substitute = $2110 N = number of rms = Till] Y = consumer income = $80,000 T = index of technology = 300 w = wage rate = $40 If the price is $100, there will be an I: of D thousand units. excess supplyr excess dem a nd

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