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Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0C and a standard deviation of 1.00C.

Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0C and a standard deviation of 1.00C. A single thermometer is randomly selected and tested. Find P99, the 99-percentile. This is the temperature reading separating the bottom 99% from the top 1%. P99 = (Round answer to three decimal places)

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