Question
Assume the network and data that follow: ACTIVITY NORMAL TIME (WEEKS) NORMAL COST CRASH TIME (WEEKS) CRASH COST IMMEDIATE PREDECESSORS A 5 $ 70 4
Assume the network and data that follow: |
ACTIVITY | NORMAL TIME (WEEKS) | NORMAL COST | CRASH TIME (WEEKS) | CRASH COST | IMMEDIATE PREDECESSORS | ||||
A | 5 | $ | 70 | 4 | $ | 80 | |||
B | 4 | 50 | 2 | 90 | A | ||||
C | 4 | 90 | 1 | 120 | A | ||||
D | 5 | 40 | 3 | 70 | A | ||||
E | 6 | 120 | 4 | 180 | B | ||||
F | 8 | 60 | 7 | 120 | D | ||||
G | 5 | 140 | 4 | 160 | C, E, F | ||||
b. | Indicate the critical path when normal activity times are used. | ||||||||
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c. | Demonstrate the crashing steps needed to minimize the cost of crashing down to various project lengths. Consider project lengths of 23, 22, 21, 20, 19, and 18 weeks. For each possible step down in project length, specify which activity would be crashed to achieve that length, compute the resultant length of each path in the project, and compute the crashing costs as shown in the table below.(Leave no cells blank - be certain to enter "0" wherever required.) |
Project Duration: | 23 Weeks | 22 Weeks | 21 Weeks | 20 Weeks | 19 Weeks | 18 Weeks | |
Length of path | ABEG | ||||||
Length of path | ACG | ||||||
Length of path | ADFG | ||||||
Activity crashed | (Click to select)AGB & FFNoneD | (Click to select)GFDNoneAB & F | (Click to select)FGAB & FNoneD | (Click to select)FB & FADNoneD | (Click to select)DNoneGAGB & F | (Click to select)FGDNoneAF | |
Crash cost for this step | |||||||
Cumulative crash cost | |||||||
Total direct cost | |||||||
d-1. | If the indirect costs for each project duration are $400 (23 weeks), $350 (22 weeks), $300 (21 weeks), $250 (20 weeks), $200 (19 weeks), and $150 (18 weeks), what is the total project cost for each duration? |
Duration | Total Costs |
23 | $ |
22 | |
21 | |
20 | |
19 | |
18 | |
d-2. | Indicate the minimum total project cost duration. | ||||||||
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