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Assume Y follows exponential distribution with a mean of 1/ . Let a>0 & b>0 be two positive constants. Show: P(Y >a+b|Y >a) = P(Y
Assume Y follows exponential distribution with a mean of 1/ .
Let a>0 & b>0 be two positive constants.
Show:
P(Y >a+b|Y >a) = P(Y >b).
(hint: the memoryless property.)
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Linear Algebra A Modern Introduction
Authors: David Poole
4th edition
1285463242, 978-1285982830, 1285982835, 978-1285463247
