Question
Assumed that you are given the following code: $ cat case_1.sh #! /bin/bash # # demonstrates how the case statement works echo -n Enter A,
Assumed that you are given the following code: $ cat case_1.sh #! /bin/bash # # demonstrates how the case statement works echo -n "Enter A, B, or C: " read letter case $letter in A) echo You entered A ;; B) echo You entered B ;; C) echo You entered C ;; *) echo You did not enter A, B, or C ;; esac echo Exiting program 75. What will be the result if you run the line below $ ./case_1.sh Enter A, B, or C: A Assumed that you are given the following code: We can use | to accept letters of either case $ cat case_2.sh #! /bin/bash # # demonstrates the use of the | (logical or) # operator in patterns within a case statement echo -n "Enter A, B, or C: " read letter case $letter in a|A) echo You entered A ;; b|B) echo You entered B ;; c|C) echo You entered C ;; *) echo You did not enter A, B, or C 8 ;; esac echo Exiting program 76. What will be the result if you run the line below $ ./case_2.sh Enter A, B, or C: A 77. What will be the result if you run the line be
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