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Assuming 100% dissociation, calculate the freezing point ( f ) and boiling point ( b ) of 3.28 AgNO3(aq) . Colligative constants can be found

Assuming 100% dissociation, calculate the freezing point ( f ) and boiling point ( b ) of 3.28 AgNO3(aq) . Colligative constants can be found in the chempendix. f= -12.20 C b=

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