Assuming you have been sent to a drinking water treatment plant in the USA for an

internship and were informed that the flow of raw water to the coagulation system is

$1\mathrm{.}0\frac{m^3}{s}.$ You are then presented with the datasheet of a polymer to be used as

coagulant and the concentration of the polymer is to be $0\mathrm{.}40m\frac{g}{L}$ on an $"$as sold"

basis. The polymer datasheet states that it is approved for clarification of potable

water at dosages $1\mathrm{.}0\frac{m}{L}$ and the polymer density $($as supplied$)$ is $1\mathrm{.}064kg$ polymer

emulsion per liter emulsion $($i$.$e$.,1\mathrm{.}064k\frac{g}{L}).$ Prove by calculation to your internship

supervisor that:

$($a$)$ The rate of feed flow of neat $($i$.$e$.,$ undiluted$)$ polymer solution is $22\mathrm{.}5m\frac{L}{m}in(4$

points$).$

$($b$)$ The amount of polymer in barrels required for $6$ months of storage is $28$ barrels if

the volume of the barrel to be used for polymer storage is $208\mathrm{.}2L(3\mathrm{.}5$ points$).$

Note: The $"$as sold" basis means as it comes out of the container. For example, a $10m\frac{g}{L}$

solution means that $10mg$ of product from the container is associated with $1000mL$ of raw

water, that is$,10mg$ product per liter of raw water.