At 1276 K, K_eq = 7.25e+00 for the reaction:

1/3 NO₂(g) + 1/3 N₂O(g) NO(g) What is the value of K_eq for the reaction 3 NO(g) NO₂(g) + N₂O(g) at this temperature?

(Explanation on how to solve this type of problem is my focus)

a) For the second reaction at this temperature K_eq = 1.94e+00. b) For the second reaction at this temperature K_eq = 3.81e+02. c) For the second reaction at this temperature K_eq = 1.38e-01. d) For the second reaction at this temperature K_eq = 5.17e-01. e) For the second reaction at this temperature K_eq = 2.62e-03.