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At 1281 o C the equilibrium constant for the reaction: 2 IBr(g) I 2 (g) + Br 2 (g) is K P = 1.07. If

At 1281 ^oC the equilibrium constant for the reaction:

2 IBr(g) I₂(g) + Br₂(g)

is K_P = 1.07. If the initial pressure of IBr is 0.00940 atm, what are the equilibrium partial pressures of IBr, I₂, and Br₂? p(IBr)= _____ p(I₂) = _____ p(Br₂) = _____

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