At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20the acceleration is exactly60mi/h².Letv(t)

be the velocity of the carthours after 2:00 PM. Then(v(1/3)v(0))/(1/30)=____.

By the Mean Value Theorem, there is a numbercsuch that0 <c<____withv'(c) =____.

Sincev'(t) is the acceleration at timet, the accelerationchours after2:00 PMis exactly60mi/h².