Answered step by step
Verified Expert Solution
Question
1 Approved Answer
. At 25 C, the aqueous solubility of TCE in water is xTCE=2x10-4 on the mole fraction scale. At 25 C, the infinite dilution activity
. At 25 C, the aqueous solubility of TCE in water is xTCE=2x10-4 on the mole fraction scale. At 25 C, the infinite dilution activity coefficient for TCE in octanol is 4. Determine the octanol/water partitioning coefficient (Kow) for TCE at 25 C. The molar volume of water is 18 cm3 /mol and the molar volume of octanol is 157 cm3 /mol. Kow = Coctanol Cwater where C is in units of concentration (e.g., mg/L or mol/L)
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started