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At 3009C the equilibrium constant for the reaction: 2BrCl(g)Br2(g)+Cl2(g) is KP=0.714. If the initial pressure of BrCl is 0.00258atm, what are the equilibrium partial pressures

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At 3009C the equilibrium constant for the reaction: 2BrCl(g)Br2(g)+Cl2(g) is KP=0.714. If the initial pressure of BrCl is 0.00258atm, what are the equilibrium partial pressures of BrCl2,Br2, and Cl2 ? p(BrCl)=p(Br2)= p(Cl2)=

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