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At 3.00atm and 651K, what volume of NO2 gas forms from 58.65g of O2 ? 4NH3(g)+7O2(g)4NO2(g)+6H2O(l) First, calculate the number of moles of NO2 formed
At 3.00atm and 651K, what volume of NO2 gas forms from 58.65g of O2 ? 4NH3(g)+7O2(g)4NO2(g)+6H2O(l) First, calculate the number of moles of NO2 formed in this reaction and show the conversions required to solve this problem. 58.65gO2(.)()molNO2 Then, use the ideal gas law to calculate the volume of NO2 gas formed. V= L
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