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At a certain temperature, the decomposition of NO 2 is second order with a rate constant of 2.85 M -1 min -1 . If one
At a certain temperature, the decomposition of NO2 is second order with a rate constant of 2.85 M-1min-1. If one starts with 2.14 M of NO2, how many minutes will it take for it to decompose to 30.0% of its initial value?
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Chemistry The Central Science
Authors: Theodore Brown, Eugene LeMay, Bruce Bursten, Catherine Murphy, Patrick Woodward
12th edition
