At a major the took random sample of 750 to estimate the number of runners who will need hotel accomadationIn the sample 66.7% of runner) responded that they would need hotel accomadations.

1. Find the 99% margin of error. (Round to 4 decimal plac
2. Construct the 99% confidence interval for the population proportion. (Round to 4 decimal places)
3. Interpret the 99% confidence interval for the population proportion.
4. What is the minimum sample of runners needed to be sampled to have a 2.5% margin of error?
5. Explain work