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At last, envision that the scientist doesn't have careful rest and response time information. That is, ceaseless information are not accessible for the two factors.

At last, envision that the scientist doesn't have careful rest and response time information. That is, ceaseless information are not accessible for the two factors. All things being equal, the individual in question possibly knows whether members had moderate or speedy response times and satisfactory or insufficient measures of rest.

Enter the accompanying dataset into SPSS, at that point lead the proper chi square investigation to respond to the inquiries and decide whether rest time is identified with response time. Make certain to completely clarify the reasoning for your response to each address, including proof from the content and Learning Activity assets.

Moderate Reaction Time

Fast Reaction Time

Satisfactory Sleep

9

5

Insufficient Sleep

6

10

Review the four sizes of estimation (i.e., ostensible, ordinal, stretch, proportion). Clarify what size of estimation is utilized to gauge rest time in this model. How would you know?

Clarify what size of estimation is utilized to gauge response time. Clarify how you know.

State whether this situation requires a decency of fit test or a trial of autonomy. Clarify your answer.

Prior to processing the chi square, express the invalid theory and elective speculation in words (not recipes).

Distinguish the acquired ?2 utilizing SPSS and report it in your answer record.

Express the levels of opportunity and clarify how you determined it by hand.

Recognize the p esteem utilizing SPSS and report it in your answer archive.

Clarify whether you ought to hold or reject the invalid speculation and why.

Are the outcomes genuinely critical? How would you know?

Clarify what you can decide about the connection between rest time and response time.

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7. Identify the mean and standard deviation of the graph. X 70 85 100 115 130 145 O mean = 100; standard deviation = 30 O mean = 85; standard deviation = 30 O mean = 100 standard deviation = 15 mean - 85; standard deviation = 15A random sample is to be selected from a population that has a proportion of successes p = 0.56. Determine the mean and standard deviation of the sampling distribution of p for each of the following sample sizes. (Round your standard deviations to four decimal places.) (0) n = 10 main standard deviation standard deviation (c) n = 30 mean standard deviation (d) n = 50 man standard deviation JOUTO (e) = 100 mean standard deviation (0) n = 200 standard deviationA population is nonnallv distributed with mean 19.2 and standard deviation 1.3. {a} Find the intervals representing one, two, and three standard deviations of the mean. one standard deviation: two standard deviations: three standard deviations: {b} 1vlll't'lat percent ofthe data lies in each of the intervals in part {a}? {Round your answers to two decimal places.) one standard deviation: two standard deviations: three standard deviations

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