At least one of your answers is incorrect. With a sample of size n, each value represents a portion of StartFraction 1 Over n EndFraction of the sample. Using the known sample size n, find the values of StartFraction 1 Over 2 n EndFraction , StartFraction 3 Over 2 n EndFraction , StartFraction 5 Over 2 n EndFraction , and so on, until reaching n values. Then use the standard normal distribution to find the z scores corresponding to the cumulative left areas. These are the z scores that are expected from a normally distributed sample. Remember to round to two decimal places and to use ascending order