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At the following location a linkage is unable to travel any further, hence the system is equilibrium due to stoppage. Solve for the linkage forces

At the following location a linkage is unable to travel any further, hence the system is equilibrium due to stoppage. Solve for the linkage forces due to the 100 in*lb torque applied at point 3 as well as the forces at points 1,2,3,4 and 5. All points can be considered to react loads. The corresponding linkage lengths and angles are labeled in the picture. The values are as follows: L1=7 in (distance from point 1 to point 2), L2=5 in (distance from point 2 to point 3), L3=6.1 in (distance from point 2 to 5), L4=1 in (distance from point 2 to point 4), Theta 1=32 degrees, Theta2= Theta3=5 degrees. Global coordinate system is labeled in the images. You are to only solve for the forces. The linkages are considered perfectly rigid so no material information is needed. Points 1-5 only react forces. Point 3 is considered a pinned joint where the applied torque is applied. I have posted this question a couple of times with no actual answers. I am needing help deriving the numerical solution using statics and free body diagrams. If someone could draw the fbds and write out the corresponding equations that would need to be solved in a system solver that would be very helpful. I have a system solver that should be able to solve the system of equations once they are all determined.
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