b$)$ Assuming a starting forecast of $51\mathrm{.}00$ for week $1$ with a smoothing constant alpha of $0\mathrm{.}60,$ the forecasts for weeks $2$ through $24$ have been developed and are provided below. Continuing with the given$$ information, the forecast for week $25$ is $($round your response to two decimal$$ places$)$:

Week

$1$

$2$

$3$

$4$

$5$

$6$

$7$

$8$

$9$

$10$

$11$

$12$

Calls

$51\mathrm{.}00$

$51\mathrm{.}00$

$40\mathrm{.}80$

$31\mathrm{.}92$

$36\mathrm{.}17$

$40\mathrm{.}87$

$36\mathrm{.}75$

$26\mathrm{.}10$

$27\mathrm{.}84$

$31\mathrm{.}54$

$25\mathrm{.}22$

$19\mathrm{.}09$

Week

$13$

$14$

$15$

$16$

$17$

$18$

$19$

$20$

$21$

$22$

$23$

$24$

$25$

Calls

$31\mathrm{.}64$

$45\mathrm{.}06$

$38\mathrm{.}42$

$30\mathrm{.}97$

$45\mathrm{.}99$

$50\mathrm{.}80$

$44\mathrm{.}92$

$39\mathrm{.}57$

$51\mathrm{.}83$

$66\mathrm{.}33$

$56\mathrm{.}53$

$46\mathrm{.}01$

$$

enter your response here

Part $4$

$$c$)$ For the forecast provided$(24$ weeks$)$ with alpha $=0\mathrm{.}30,$ MAD $=$

$$

enter your response here calls $($round your response to two decimal$$ places$).$

Part $5$

For the forecast provided$(24$ weeks$)$ with alpha $=0\mathrm{.}60,$ MAD $=$

$$

enter your response here calls $($round your response to two decimal$$ places$).$

Part $6$

Based on the MAD values$$ only, alphaequals

$$

$0\mathrm{.}30$

$0\mathrm{.}60$

should be used.

Part $7$

Given that the actual calls during week $25$ were $81,$ alphaequals

$$

$0\mathrm{.}30$

$0\mathrm{.}60$

yielded the closest value.