(b) Consider a linear differential equation i(t) = Ax(t) where x = R and A solution of this differential equation for the initial condition x(0) = [1 2] is x1(t) = [ 6e3-5e-t 3e3-5e-t Instead, the solution for the initial condition 2(0) = [21] is x2(t) = [ 2e3t e3t The