b - Google Docs ment/d/1QM5J60A09350qF41ecwmQ8Koqxrzn7MrmT02eIRT6RE/edit Normal text 1 Tools Extensions Help W S # 3 Arial X E = + D Part. 3. Solve the following problems based on the data you collected in the simulation experiment Part 1. SH is specific heat.. M20 X SHX (T-T) H0 and N MX SH X (T - T)metal So, QH20 =-Qmetal The metal or glass loses heat while the water gains heat. The negative means heat loss. We also use the specific heat of water SH = 4.18 J/g C. 10.5 + 1. Q for Part 1. Number 1. Is H20 So, for Part 1 we find Q of water: Make sure to use the initial and final temperature of the water only. 2. Q20 for Part 1. Number 2. Is CH20 3. Q for Part 1. Number 3. Is = - Qmetal SO, QH20 = - Solve for SH so SH metal = 1. 2. 3. Now we can find the specific heat for the material used in the experiment by therefore, - MX SHmetal X (T, QHZO 2 S4 $ R B I U A F % 5 So, for Part 1 we can now find SH of each material: Make sure to use the initial and final temperature of the material o