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b) Show how to prepare octadecyl stearate by using linoleic acid (18:2) as the only starting material. CH3(CH2)16-C-(CH2)7CH Octadecyl stearate

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b) Show how to prepare octadecyl stearate by using linoleic acid (18:2) as the only starting material. CH3(CH2)16-C-(CH2)7CH Octadecyl stearate

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