(b) Use the below output to test the null hypothesis H. : 3x -0.53w = -0.5 against the two tailed alternative H : Bx -0.53w # -0.5 at a 1% significance level. Be sure to explain how you have been able to make use of the output given. (10 MARKS) Note the variable Wplushal / X = W +0.5X Call: Im(formula - YX + 2 + Wplushalfx) Residuals: Min 10 Median 30 Max -1.8984 -0.4832 0.2532 0.5756 2.0092 Coefficients: Estimate Std. Error t value Pr(>1t1 (Intercept) 4.67189 1.66765 2.801 0.0099 ** x -0.63364 0.39078 -1.621 0.1180 Z -2.51074 0.04934 -50.885