Background calculations The potential across a capacitor is proportional to the charge on the capacitor: Va = 0/6 So, in a series RC circuit the relationship between the potential and the current is: 1 t J' J' V66) 2 116(0) +Efo1t )dt The resistor, capacitor, and driving frequency in this experiment are chosen so that the current in the . . . . . . V ' r . . . . circuit is limited by the resistor, so I (t) = %. If the di'iVing potential is constant, then 1V - veto = we) +E\"\";;\"e\"t 1. Assume that _W= 2V, R=1000 Q and C = 2.23:10'6 F, and 143(0) 2 0, Assuming also that the current is limited entirely by the resistance, calculate the charge on the capacitor after 5.0}(10'4 s. 5 Q = (V 2. Assuming the same conditions as above, calculate the potential across the capacitor after 5.0){10'4 s. VC : V 3. Sketch the expected signal 011 the grid to the right for the parameters above if the applied voltage is a square wave that starts at time =0 at and switches from +2.0 V to -2.0V at 5.0)(10'4 s and then back to + 2V at ICIXIO'4 s