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Balance the following reaction: C9H20(g) + O2(g) = CO2(g) + H2O(g) and indicate: If you initially have 130 g of hydrocarbon 85 g of oxygen.

Balance the following reaction: C9H20(g) + O2(g) = CO2(g) + H2O(g) and indicate:
If you initially have 130 g of hydrocarbon 85 g of oxygen.
a) What is the limiting reactant? (do the math)
b) How many grams of CO2 are formed?
c) How many moles of CO2 do those grams represent?
d) How many liters of water are formed and how much of the excess reagent remains?

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a C9H20g O2g CO2g H2Og After balancing the equation will be C9H20 g 14O2g 9CO2g 10H2Og Amount of Hyd... blur-text-image

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