BASIC Now that hoverboards exist, we can use them to design fun but extremely dangerous rides! A strong spring is attached to a rotating post, and the other end to someone standing on a hoverboard. Tethered to the post, and riding frictionlessly a few cm above the ground, the rider can be pulled around in a circle at an exciting speed, and the faster he goes, the more the spring stretches, and the bigger the circle. L 4x (length of spring when not (how far spring has stretched) stretched) spring hoverboard rotating post r (radius of cirular path)In the diagram, L = 2.00 m is the length of the spring when not stretched. When the rider is going around in a circle, the spring stretches by an amount Ax, and the spring exerts an elastic force F E = k Ax on the rider, where k is the spring constant (stiffness) of the spring. (1) RNG There are four randoms to choose and identify: - The mass m of the (adult) hoverboard rider. The mass of the hoverboard can be ignored. After a brief speed-up from rest, the rider will sail around at the ride's minimum speed vmm for a time, with the spring at its minimum stretch Axmin = 1-3 m, then gradually accelerate to its maximum speed vmax, when the spring is stretched to its maximum extent, Axmax = 5-7 m. Pick Axmm and Axum. The magnitude of the rider's maximum acceleration is amax = Xg, rounded to 3 SF, where X is a 3 SF SIST random number between 5-8. NoFor example, if you could pick X = 3.72, then you'd get amax = 3.72 g = 3.72 x 9.81 m/s = 36.5 m/sList your random m, Axmin, AXmax, and amax here. POSTDO NOT ASSIST DO NOT POST DO NOT ASSIST (2) Draw a FBD of the rider, and use it along with N2L to calculate the spring constant k.ST DO NOT ASSIST (3) Calculate the rider's maximum speed Vmax, which occurs when his acceleration is amax, at maximum stretch. (4) Now calculate the minimum translational acceleration amin and speed min of the rider, assuming that the rider moves in a circle at constant speed after the ride slows down so the spring is at its minimum stretch. (5) At which stretch, maximum or minimum, does the rider take more time to complete one revolution? Prove your conclusion by direct calculation. DO NOT POST DO NOT ASSIST DO NOT POST DO NOT ASSIST DO NOT POST DO NOT ASSIST DO NOT POST DO NOT ASSIST DO NOT POST DO NOT ASSIST Checks: amax > amin, and Vmax > Vmin. DO NOT POST DO NOT ASSIST DO NOT POST DO NOT ASSIST Tips & hints: As its name implies, the spring constant k doesn't change, and k can't be negative. 1D kinematics doesn't apply to uniform circular motion. Finally, / and Ax are not equal: see the diagram