Question
Bayus (1991) studied the mean numbers of auto dealers visited by early and late replacement buyers. Letting be the mean number of dealers visited by
Bayus (1991) studied the mean numbers of auto dealers visited by early and late replacement buyers. Letting be the mean number of dealers visited by all late replacement buyers, set up the null and alternative hypotheses needed if we wish to attempt to provide evidence that differs from 4 dealers. A random sample of 100 late replacement buyers yields a mean and a standard deviation of the number of dealers visited of x = 4.38 and s = .61. Using a critical value and assuming approximate normality to test the hypotheses you set up by setting equal to .10, .05, .01, and .001. Do we estimate that is less than 4 or greater than 4? (Round your answers to 3 decimal places.)
Ho: 4 versus Ha: 4. \begin{tabular}{|l|l|} \hline & \\ \hline ta/2=0.05 & \\ \hline ta/2=0.025 & \\ \hline ta/2=0.005 & \\ \hline ta/2=0.0005 & \\ \hline \end{tabular} There is evidence. is 4Step by Step Solution
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