Question
BCl3 +LiAlH4 -> B2H6 + LiAlCl4 calculate the moles of BCl3 that will be required to produce 985grams of B2H6
BCl3 +LiAlH4 -> B2H6 + LiAlCl4
calculate the moles of BCl3 that will be required to produce 985grams of B2H6
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sol Given mass of B H 6 Molar mass of BH 27 moles BH6 35611 LI XI C 11 985 ...Get Instant Access to Expert-Tailored Solutions
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