Below are tables that represent the contents of our two tables. For simplicity, BusinessEntityID are a numeric field, and the rest are VARCHAR fields. (I will use quotes around their values as a reminder) If there is nothing written for a column in a particular row, consider the value to be NULL. (i.e. it has NO value) Person.Person 

BusinessEntityID	FirstName	LastName
1	"Belinda"	"Wood"
2	"David"	"Townsend"
3	"Josh"	"Mack"
4	"Ida"	"Gutierrez"
5	"Dominick"	"Morris"
6	"Virgil"	"Beck"
7	"Francis"	"Mills"
8	"Donna"	"Malone"
9	"Renee"	"Gross"

Person.EmailAddress

BusinessEntityID	EmailAddress
1	"belinda.wood@email.com"
2	"david.townsend@email.com"
4	""
5
6	"virgil.beck@email.com"
6	"virgil.b.beck@email.com"
7	"francis.mills@email.com"
8	"NULL"

What are the results of the following queries? Each question is worth up to 1 bonus point toward assignments. Q1) SELECT p.FirstName, p.LastName, ea.EmailAddress FROM Person.Person p LEFT OUTER JOIN Person.EmailAddress ea ON p.BusinessEntityID = ea.BusinessEntityID WHERE ea.EmailAddress LIKE NULL Q2) SELECT p.FirstName, p.LastName, ea.EmailAddress FROM Person.Person p INNER JOIN Person.EmailAddress ea ON p.BusinessEntityID = ea.BusinessEntityID WHERE ea.EmailAddress IS NULL Q3) SELECT p.FirstName, p.LastName, ea.EmailAddress FROM Person.Person p LEFT OUTER JOIN Person.EmailAddress ea ON p.BusinessEntityID = ea.BusinessEntityID WHERE ea.EmailAddress IS NULL Q4) SELECT p.FirstName, p.LastName, ea.EmailAddress FROM Person.Person p LEFT OUTER JOIN Person.EmailAddress ea ON p.BusinessEntityID = ea.BusinessEntityID AND ea.EmailAddress LIKE NULL Q5) SELECT p.FirstName, p.LastName, ea.EmailAddress FROM Person p LEFT OUTER JOIN EmailAddress ea ON p.BusinessEntityID = ea.BusinessEntityID