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Below is a proposal of a new elegant sorting algorithm from a paper under review at a major computer science conference: import math def swap(A,i,j):A[j],A[j]=A[j],A[j]
Below is a proposal of a new elegant sorting algorithm from a paper under review at a major computer science conference: import math def swap(A,i,j):A[j],A[j]=A[j],A[j] def dupessert (seq,i,j) : if seq[i]>seq[j] : swap(seq,i,j) if i+1>=j : return k= math.fleor ((ji+1)/3) \# round down dupessort(seq, i, j-k) \# first 2/3 dupessort(seq, i+k,j) \# last 2/3 dupesert(seq, i, j-k) \# first 2/3 again (a) Argue that, if n is the number of elements in the input sequence seq, then dupesort(seq, 0n1) correctly sorts the input sequence. (b) Give a recurrence for the worst-case running time of dupesort and a asymptotic bound on the worst-case running time. (c) Compare the worst-case running time of dupesort with that of insertion sort, merge sort, heapsort, and quicksort. Shojuld the paper be accepted
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