Below is a sample of 25 sample means. Each sample is based on a sample of two scores. These were drawn from the population of scores (composed of values 2.3.4.5, and 6] and it has a u = 4 and a o = 1.41. I have taken all possible combinations of the scores, so the table below reects all possible values contained in the Sampling Distribution. The Mean of this Sampling Distribution is: Table: A Sampling Distribution of the Means (all possible combinations) Sample Scores Sample Sample Scores Sample Number Sampled Mean Value Number Sampled Mean Value 1 2,2 2 14 4,5 4.5 2 2,3 2.5 15 4,6 5 3 2,4 3 16 5,2 3.5 4 2,5 3.5 1? 5,3 4 5 2,6 4 18 5,4 4.5 6 3,2 2.5 19 5,5 5 ? 3,3 3 20 5,6 5.5 8 3,4 3.5 21 6,2 4 9 3,5 4 22 6,3 4.5 10 3,6 4.5 23 6,4 5 11 4,2 3 24 6,5 5.5 12 4,3 3.5 25 6,6 6 13 4,4 4 Using the Sampling Distribution above, what is the probability of drawing a sample mean = 6? O a. p = .0228 O b. .025 O c. .05 O d. .078 Using the Sampling Distribution from Q#1, having drawn at random a sample mean of 6, if you drew a 95% Confidence Interval around it, O a. it would include | = 4 O b. it would include u but a y that would not be equal to 4 C. it would not include u but would include a sample mean equal to 4 O d. we can't know because we can't draw a .95 CI because we don't actually know the true standard error Having drawn a random sample (see Q#5), the 95% confidence interval stretches from O a. 3.24 to 8.79 O b. 4.04 to 7.96 O c. 5.95 to 6.05 O d. As noted in Q#5, we cannot calculate the 95% Confidence Intervals