Question
Below is all 3 shapes. If someone can help me put it the way it is ask. This is the X pattern. import java.util.Scanner; class
Below is all 3 shapes. If someone can help me put it the way it is ask.
This is the X pattern.
import java.util.Scanner;
class acdf {
public static void main(String[] args) {
Scanner s = new Scanner(System.in);
System.out.println("enter the number of rows=column");
int n = s.nextInt();
int i, j;
s.close();
for (i = 1; i
for (j = 1; j
if (j == i) {
System.out.print("*");
} else if (j == n - (i - 1)) {
System.out.print("*");
} else {
System.out.print(" ");
}
}
System.out.println();
}
}
}
The last one is the Diamond pattern
import java.util.Scanner; public class newstar { public static void main(String agrs[]) { Scanner in = new Scanner (System.in);
System.out.print("Enter Number: "); int inp = in.nextInt();
int wan = 1; int space = inp ;
for(int i = 0; i
for(int s = 0; s
}
}
if(i == inp-1) { break; } else{ System.out.println(); wan=wan+2; space--; }
}
//second
int x = (inp * 2) - 1;
int y = 1;
for(int l = 1; l = 1; s--) { System.out.print(" "); }
for(int s = 0; s = 1) { if(s == 0 || s == x - 1) { System.out.print("*"); } else { System.out.print(" "); }
}
} System.out.println();
x-=2;
y++;
}
}
}
1 public class Box 3 {public int size = 0; public void printBox() 6 {for(int i = 0; iStep by Step Solution
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