Bergen Community College Mail - (no subject) (a) State the parameter our confidence interval will estimate. (b) What type of an interval can be constructed for this parameter? Why? (c) Find the mean and the margin of error for an 80% confidence interval. (d) Firrally, put all the pieces together for an 80% confidence interval for the mean doctor visit amount. (you may leave your answer in +- form.) Bonus: If the irate patient would like to narrow the confidence interval for the sample mean, what can she do? 17. Multi-part - ANSWER ALL PARTS A recent survey of 90 randomly selected families showed that 20 did not own a single television set and used alternative devices for entertainment. Find the 98% confidence interval of the true proportion of families who do own a television set. (a) State the parameter the confidence interval will estimate. (b) Identify the conditions that must be met to use this procedure and explain how you know that each one has b satisfied. (c) Find the point estimate and the margin of error for a 98% confidence interval. (d) Estimate the true proportion of families who do not own a television set. State your answer in the context of setting.Stions: Answer all questions. Question 11-15: Short answer Question 16&17: Multi-part 11. What is the critical value of t-distribution for an 99% confidence interval for sample of 5? 12. A pizza shop owner wishes to find the 95% confidence interval of the true mean cost of a large cheese pizza. How large should the sample be if she wishes to be accurate to within $0.10? A previous study showed that the standard deviation of the price was $0.28. 13. True or false: Interval estimates are preferred over point estimates since a confidence level can be specified. Explain the reasoning for your selection. 14. A survey of 12 riding lawn mowers found that the average number of gallons per hour was 1.21 and the standard deviation was 0.4. Based on this survey, find the point estimate for a 90% confidence of the population true mean number of gallons per hour Here's the dot plot of the sample data 15. A random sample of 20 of the record high temperatures in the United States had a mean of 114.6 degrees Fahrenheit and the standard deviation to be s = 8.22. Find the standard error of x for constructing a 95% confidence interval for true mean highest temperature. 2.0 9 3 16. Multi-part - ANSWER ALL PARTS An irate patient complained that the cost of a doctor's visit was too high. She randomly surveyed 20 other patients and found that the mean amount of money they spent on each doctor's visit was $44.80. The standard deviation of the sample was $3.53. Assume the variable is normally distributed. ps://mail.google.com/mail/u/0?ikabc6d 177346&view=pt&searchallSpermmagid=mag-1934170276860943898236 1.&simplemsg 24170127080904
