Biomechanics Final Formula Sheet Conversions, Constants, and Steps to Solving Problems 1 in = 2.54 cm; 1 m = 3.3 ft; 1 km = 0.62 mi 1 1b = 4.45 N = 0.454 kg; 1 kg = 2.2 Ibs 1 m/s = 3.6 km/h = 2.2. mph It rad = 180 = 1/2 rev ag = -9.81 m/s? Length CF = (Real Length) / (Viewed Length) * Time CF = (Time) / (Pictures) Solving Problems (FGPAURHS) Linear Motion *Vav = Ap / At = SL * SR; Ap = Vav At between Vit.5 = Pi+1 - Pi @ Vi = pi +1 - Pi-1 ti + 1 -ti ti+ 1 -ti-1 dav = Av / At; Av = davAt between ait.5 = Vi+1 - Vi @ aj = Vi+1 - Vi-1 ti + 1 -ti ti+1-ti-1 * Trapezoid Rule Atrapeziod = (bi+1 - bi)(hi) + (1/2)(bi+1 - bi)(hi+1 - hi) Center of Mass Xscm =Xp - ((Xp - Xd) * cm%), ysem = yp - ((yp - yd) * cm%) XTBCM = (Emix; )IM , yTBCM = (Em; y; )IM * Projectile Motion * vi = vit alt * vi = v2 + 2a(pf- pi) * pf = pi + viAt + 1/2 aAt2, Angular Motion SOH CAH TOA Pythagorean Theorem a2 + 62 = c2 Law of Cosines a = Vb+c- -2bccost b 0 = tan"'((yp - ya)/(Xp-Xd)) Sine Rule sina sin B siny Under linear motion may replace p, v, and a with 0, @, a OHip = 0Thigh - O Trunk; 0 Ankle = 0Foot - 0Shank - 90 OKnee = 0Thigh - 0Shank; ORF = 0Shank - OCalcaneus of = wi - at Of = 0; + wiAt + 1/2 aAt2 of = 02+ 20(0f- 01) s = 10 aT = ra VT = IQ Force ac = r @= = VT-/I EF=ma Ff = UFN M = T = (F*d)I EM=Ia, ET=IaPicture 31. What was the step rate? a. 0.8333 steps/s b. 1.2 steps/s c. 0.6 steps/s 1.6667 steps/s None of the above a, g last? 6. b, c, or dis correct ...................................................... 32. How long did left swin 21. 0.83335 b. 405 0. 0.66675 d. 1.66675 e. None of orrect ................................................ the above a, b, c, or dis 0 7. An analysis of a runner reveals the following: Displacement was 5 m. The number of strides was 3 and the time needed to cover the 5 m was 1.8 s. What was their step rate? a. 2.78 steps/s b. 1.67 steps/s c. 0.7 steps/s d. 3.33 steps/s e. None of the above . of the gait cycle? VC. C d. D e. E ..... 20. For the above picture given a short period of time to make a difference which projectile motion factor likely should be the focus of training for the long jump? a. v b. B C. d. D. e. None of the above .... 21. Video analysis is used to analyze a running long jump. You know the following. The takeoff height was 1.6 m, the resultant velocity at takeoff was 7.2 m/s, the vertical velocity at takeoff was 4 m/s, the horizontal velocity at takeoff was 6 m/s and the time the jumper was in the air was 4.2 s. How far did they jump? a. 9.6 m b. 16.8 m c. 30.3 m d. 25.2 m e. Cannot be determined from the information provided 22. A long jumper is running at 10 m/s and has a takeoff angle of 23 deg. What was their horizontal velocity at takeoff? a. 3.9 m/s b. 9.2 m/s c. 10.0 m/s d. 10.86 m/s e. None of the above .......... 23. Video analysis is used to analyze a basketball player's jumping prior to beginning her training macrocycle. If her total time in the air was 0.4 s what was her jump height? a. 0.1962 m b. 0.49 m do c. 0.981 m d. 1.962 m e. None of the above.14. As a golfer examines a shot it is noticed that the putting green is above the current lie of the ball. Assuming air resistance is negligible the optimum angle at which the ball flies off is a. Greater than 45 degrees b. Less than 45 degrees c. 45 degrees d. Both B or C e. None of the above ........... 11 block height (jump & reach height) what factor(s) must beC. d. I, II, III, IV e. None of the above a-d... 16. At the beginning of a 100 m race in which the runners are speeding up in the positive direction the velocity is positive and the acceleration is negative. At the end, when they are slowing down, the velocity and acceleration would both be negative. a. Both statements are true b. Statement 1 is true, statement 2 if false c. Statement 1 is false, statement 2 is true d. Both statements are false 17. When a strength and conditioning coach wants to determine the value of a particular streng program the most important value to measure is jumper flight height. Flight height is completely determined by the difference between takeoff height and landing height. a. Statement 1 is true, Statement 2 is true b. Statement 1 is true, Statement 2 is false c. Statement 1 is false, Statement 2 is true d. Statement 1 is false, Statement 2 is false 18. If a baseball was thrown into the air with a projection angle of 60 degrees, what can be assumed about the characteristics of the projectile? a. The object will only go forward and down b. The object will only go forward up and down c. The object will travel in a symmetrical parabola d. The object will travel the same distance in the horizontal and vertical direction e. None of the above..e. None of above 5. In Running Right Single Support is defined by a. Left Heel Strike to Right Heel Strike b. Right Heel Strike to Right Toe Off c. Right Toe Off to Right Foot Strike d. Left Toe Off to Right Foot Strike e. All of the above are true.............. 6. In walking how is the period of double support defined? a. Left Toe Off to Left Heel Strike b. Right Heel Strike to Left Toe Off c. Left Heel Strike to the next Left Heel Strike bas Fusco d. Left Toe Off to Right Heel Strike e. None of above ........The following gait data was recorded. Event Time RFS1 0 RTO1 0.2 LFS1 0.283 LTO1 0.5 RFS2 0.567 RTO2 0.784 LFS2 0.867 LTO2 1.084 RFS3 1.151 10. What kind of pattern does the gait data present? a. Running b. Walking c. Cannot be determined based on the information presented d. None of the above. . . . . . . . . ........3:39 PM Thu Nov 10 K Georgia Southern University 76% Yesterday 9:17 AM LIVE only what Is nce i Edit Picture time(s) position(m) velocity 3 0.15 .34 4 0.20 1.34 0.25 1.27 -1.4 6 0.30 1.18 - 18 0.35 1.27 0.40 1.30 0.45 1.30 27. What is the distance the person traveled from picture 4 to picture 8? a. -0.04 m b. 0.04 m C . -0.07 m d. 0.28 m e. None of the above a, b, c, or d is correct . 28. What is the acceleration at picture 5? a. -1.6 m/s 2 b. 29 m/s 2 c. 7 m/s 2 d. 1.3 m/s 2 e. None of the above a, b, c, or d is correct 29. What is the time of the velocity between Picture 6 and Picture 7 a. 0.3 s b. 0.325 s C. 0.35 s d. 6.5 s e. None of the above a, b, c, or d is correct30. Calculate the runners velocity after Is (starting at 0 m/s) given the following Accel - Time graph Acceleration - Time Graph of a Person Walking OTJ 3.5 OTA Acceleration (m/s 2) 0.5 O -0.5 0/5 1/5 -1.5 Time (s) a. 1.75 m/s b. 1 m/s c. 0.75 m/s d. 1.125 m/s e. None of the above a, b, c, or d is correct