Business stats

A researcher claims that a post-lunch nap decreases the amount of time it takes males to sprint 20 meters after a night with only 4 hours of sleep. The table shows the amounts of time (in seconds) it took for 10 males to sprint 20 meters after a night with only 4 hours of sleep when they did not take a post-lunch nap and when they did take a post-lunch nap. At a = 0.05, is there enough evidence to support the researcher's claim? Assume the samples are random and dependent, and the population is normally distributed. Complete parts (a) through (e) below. Male 9 10 Sprint time (without 4.08 4.06 3.93 3.93 3.99 3.98 3.91 4.04 4.07 4.08 nap) Sprint time (with nap) 3 93 307 3.87 3.86 3.98 3 86 3 77 3.90 3 98 3.98 (a) Identify the claim and state Ho and Ha What is the claim? A. A post-lunch nap decreases the amount of time it takes males to sprint 20 meters. O B. A post-lunch nap increases the amount of time it takes males to sprint 20 meters. O C. A night with only 4 hours of sleep increases the amount of time it takes males to sprint 20 meters. D. A night with only 4 hours of sleep decreases the amount of time it takes males to sprint 20 meters. Let py be the hypothesized mean of the difference in the sprint times (without nap - with nap). What are Ho and H,? OA Ho Ho 20 OB HO H. SO OC. Ho MJ # 0 Ha Ha d (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in any answer boxes to complete your choice. (Round to three decimal places as needed.) OA +> O B. O C. to (c) Calculate d and sa d= (Round to three decimal places as needed.) Calculate Sd- SJ =(Round to three decimal places as needed.) (d) Find the standardized test statistic t. *=(Round to three decimal places as needed.) (e) Decide whether to reject or fail to reject the null hypothesis and interpret the decision in the context of the original claim. the null hypothesis. There V enough evidence to the claim that a the amount of time it takes males to sprint 20 meters Next Type here to search 76'F Mostly sunny 3:14 PM