$C{H}_3\frac{C}{O}OH+C_2{H}_{5}OHlongrightarro{w}^{[H_3{O}^{+}]}C{H}_3\frac{C}{O}O{C}_2{H}_5+H_{2}O$

Following mixtures were prepared and titrated with $0\mathrm{.}953$MNaOH solution to calculate equilibrium constant of the reaction.

Mixture $1,2\mathrm{.}5ml3MHCl+2\mathrm{.}5ml$ Water

Mixture $2.2\mathrm{.}5mL3MHCl+2ml$ Ethyl Acetate $+0\mathrm{.}5ml$ Acetic Acid

$K_x=\frac{x_{C{H}_3\frac{C}{O}O{C}_2{H}_5}{x}_{H_{2}O}}{x_{C_2{H}_{5}OH}**x_{C{H}_3\frac{C}{O}OH}}$