Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

C++ Interactive Coding and Question : Change SquareContainer::iterator::operator*() so that it is a const method. What is this supposed to mean? When you try to

C++

Interactive Coding and Question: Change SquareContainer::iterator::operator*() so that it is a const method. What is this supposed to mean? When you try to compile and run the program, what happens? Does this appear to be consistent with the declaration of that operator as const? Why or why not? In your opinion, should that operator be declared const?

SquareContainer2.h

#pragma once template class SquareContainer { public: class iterator; // forward declaration friend class iterator; // friend declaration /*! @class iterator This is a nested class. Note that it is in the public section of SquareContainer */ class iterator { public: /*! Initializes the iterator by associating it with a SquareContainer object, starting it at the beginning. */ iterator(SquareContainer* c, unsigned xloc = 0, unsigned yloc = 0) : theContainer(c), x(xloc), y(yloc) {} // You may need a copy constructor; we don't have it here // iterator(const iterator& it); // Prefix form of "next" operator iterator operator++(); // Postfix form of "next" iterator operator++(int); // Returns the current item T& operator*() const; // Comparison operators bool operator==(const iterator& rhs) const; bool operator!=(const iterator& rhs) const; private: /*! Keep track of where we are in theContainer */ unsigned x, y; /*! The SquareContainer object this iterator is associated with */ SquareContainer* theContainer; }; //Returns iterator that refers to first item, using iterator constructor iterator begin(void) { return iterator(this); } const iterator end(void) { return iterator(this, 0, ySize); } private: static const unsigned xSize = 5; static const unsigned ySize = 5; T contents[xSize][ySize]; }; // Remember, we can't compile template classes separately, so we // include it here and don't mention it on the command line. #include "SquareContainer2.cpp"

----------------------------------------------------------------------------------------------

SquareContainer2.cpp

#include #include using namespace std; #include "SquareContainer2.h" // Prefix form of "next" operator template typename SquareContainer::iterator SquareContainer::iterator::operator++() { // Don't do anything if we're already past the end if (y < theContainer->ySize) { if (++x >= theContainer->xSize) { x = 0; y++; } } return *this; } // Postfix form of "next" template typename SquareContainer::iterator SquareContainer::iterator::operator++(int) { iterator returnValue = *this; // Don't do anything if we're already past the end if (y < theContainer->ySize) { if (++x >= theContainer->xSize) { x = 0; y++; } } return returnValue; } // Returns the current item template T& SquareContainer::iterator::operator*() { // If we're past the end, it's really an error. You could throw an // exception, if you like. Make sure you document the iterator's // behavior in these circumstances. if (y >= theContainer->ySize) { cerr << "Attempt to dereference bad iterator; x=" << x << ", y=" << y << endl; exit(EXIT_FAILURE); } return theContainer->contents[x][y]; } template bool SquareContainer::iterator::operator==(const iterator& rhs) const { return (theContainer == rhs.theContainer) && (x==rhs.x) && (y==rhs.y); } template bool SquareContainer::iterator::operator!=(const iterator& rhs) const { return (theContainer != rhs.theContainer) || (x != rhs.x) || (y != rhs.y); }

----------------------------------------------------------------------------------------------

IteratorTest.cpp

#include using namespace std; #include "SquareContainer2.h" int main() { // You create a container like so: SquareContainer mc; // and use it in various ways: SquareContainer::iterator ci = mc.begin(); unsigned i = 1; while (ci != mc.end()) { cout << "Setting element " << i << endl; *(ci++) = i++; } for (SquareContainer::iterator ci = mc.begin(); ci != mc.end(); ++ci) { cout << *ci << endl; } }

----------------------------------------------------------------------------------------------

NoTemplate/IteratorTest.cpp

#include  using namespace std; #include "SquareContainer2.h" int main() { // You create a container like so: SquareContainer mc; // and use it in various ways: SquareContainer::iterator ci = mc.begin(); unsigned i = 1; while (ci != mc.end()) { cout << "Setting element " << i << endl; *(ci++) = i++; } for (SquareContainer::iterator ci = mc.begin(); ci != mc.end(); ++ci) { cout << *ci << endl; } }

----------------------------------------------------------------------------------------------

NoTemplate/SquareContainer2.cpp

#include  #include  using namespace std; #include "SquareContainer2.h" // Prefix form of "next" operator SquareContainer::iterator SquareContainer::iterator::operator++() { // Don't do anything if we're already past the end if (y < theContainer->ySize) { if (++x >= theContainer->xSize) { x = 0; y++; } } return *this; } // Postfix form of "next" SquareContainer::iterator SquareContainer::iterator::operator++(int) { iterator returnValue = *this; // Don't do anything if we're already past the end if (y < theContainer->ySize) { if (++x >= theContainer->xSize) { x = 0; y++; } } return returnValue; } // Returns the current item int& SquareContainer::iterator::operator*() { // If we're past the end, it's really an error. You could throw an // exception, if you like. Make sure you document the iterator's // behavior in these circumstances. if (y >= theContainer->ySize) { cerr << "Attempt to dereference bad iterator; x=" << x << ", y=" << y << endl; exit(EXIT_FAILURE); } return theContainer->contents[x][y]; } bool SquareContainer::iterator::operator==(const iterator& rhs) const { return (theContainer == rhs.theContainer) && (x==rhs.x) && (y==rhs.y); } bool SquareContainer::iterator::operator!=(const iterator& rhs) const { return (theContainer != rhs.theContainer) || (x != rhs.x) || (y != rhs.y); }

----------------------------------------------------------------------------------------------

NoTemplate/SquareContainer2.h

#pragma once class SquareContainer { public: class iterator; // forward declaration friend class iterator; // friend declaration /*! @class iterator This is a nested class. Note that it is in the public section of SquareContainer */ class iterator { public: /*! Initializes the iterator by associating it with a SquareContainer object, starting it at the beginning. */ iterator(SquareContainer* c, unsigned xloc = 0, unsigned yloc = 0) : theContainer(c), x(xloc), y(yloc) {} // You may need a copy constructor; we don't have it here // iterator(const iterator& it); // Prefix form of "next" operator iterator operator++(); // Postfix form of "next" iterator operator++(int); // Returns the current item int& operator*() const; // Comparison operators bool operator==(const iterator& rhs) const; bool operator!=(const iterator& rhs) const; private: /*! Keep track of where we are in theContainer */ unsigned x, y; /*! The SquareContainer object this iterator is associated with */ SquareContainer* theContainer; }; //Returns iterator that refers to first item, using iterator constructor iterator begin(void) { return iterator(this); } const iterator end(void) { return iterator(this, 0, ySize); } private: static const unsigned xSize = 5; stat const unsigned ySize = 5; int contents[xSize][ySize];

};

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Guide To Client Server Databases

Authors: Joe Salemi

2nd Edition

1562763105, 978-1562763107

More Books

Students also viewed these Databases questions

Question

what are the legal return types of a constructor in c + + ?

Answered: 1 week ago

Question

2. What are your challenges in the creative process?

Answered: 1 week ago