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C++ One of your friends wrote a simple Fahrenheit to Celsius temperature converter. The problem is that it is faulty. Click Grade Code now to
C++
One of your friends wrote a simple Fahrenheit to Celsius temperature converter. The problem is that it is faulty. Click "Grade Code" now to observe the test cases that your friend's solution passes and those that it fails. Can you determine where your friend went wrong in their implementation?. The faulty calculator is defined within named blocked of code, a function. The Fahrenheit value to be converted is passed as an argument to the function Fahrenheittocelsius. During this process, the parameter kFahrenheitvalue is initialized with the argument. Therefore, calling Fahrenheittocelsius(32) means that kFahrenheitvalue will take on the value 32. I understand that we haven't discussed functions in detail yet. What you need to know is that our auto-grader will invoke Fahrenheittocelsius with different values. You need to ensure that you correct the implementation (code presenting between the curly braces) such that Fahrenheittocelsius performs temperature conversions accurately. Do not change the type of the parameter (i.e., keep kFahrenheitvalue typed const int). 1 - double FahrenheitToCelsius(const int kFahrenheitValue) { // do not modify the parameter list 2 3 double celsius_value = (kFahrenheitValue - 32) * 5 / 9; // this doesn't look right... 4 return celsius_value; 5 6 } 7Step by Step Solution
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