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C++ please!! (1) (2) (3) (4) You are given a string of length 3. Print the middle 3 characters if the length is odd or

C++ please!!

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You are given a string of length 3. Print the middle 3 characters if the length is odd or the middle 2 characters if the length is even. strings.cpp Write the function insideOut(). If a string size is even and two or more, the middle two characters are removed and placed at the back and front of the result. If the size is odd and three or more, then the middle three characters are removed. The first is placed at the back of the string, the last is placed at the front, and the middle one is discarded. Here are some examples: main.cpp Suppose you want to remove extra spaces at the begnning or end of a string. Java has the trim() method to do this, but C++ does not. However, you can use the substr() member function, along with the two member functions find_first_not_of() and find_last_not_of() to write your own. 1. Find the position of the first non-space character. 2. Find the position of the last non-space character. 3. Use substr( ) to produce a new string. Write the function processName(). It's input is a full name in the form (First MI. Last). Your job is to use string member functions to break the name into the first name, last name and middle initial, and return the processed name in the form "Last, First Ml.". Use the string member functions substr(), find(), rfind(), find_first_not_of(), find_last_not_of() and at () to solve this problem. You may assume: - that every name will have exactly one word for the first and last names and a single character, followed by a period for the middle initial. - There will be at least one space separating each of the portions of the input name, but there may be more spaces. main.cpp

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